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0 votes
5.6k views
in Physics by (30.6k points)

If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :

(1) [M2] [L–1] [T0

(2) [M] [L–1] [T–1

(3) [M] [L0] [T0

(4) [M2] [L–2] [T–1]

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1 Answer

+1 vote
by (30.7k points)

Option : (1) [M2] [L–1] [T0]

E = energy = [ML2T–2

G = Gravitational constant = [M–1L3T–2

So,

E/G = [E]/[G]

= ML2T–2/M–1L3T–2

= [M2L-1T0]

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