If f(x) = (1 - sin x)/(π - 2x)^2, for x ≠ π/2, is continuous

Question

If \(f(x) = \frac{1 - sin\,x}{(\pi - 2x)^2},\) for x ≠ \(\frac{\pi}{2},\) is continuous

If f(x) = (1 - sin x)/(π - 2x)², for x ≠ π/2, is continuous

at x = \(\frac{\pi}{2},\) then find \(f\left(\frac{\pi}{2}\right).\)

Answer 1

If f(x) = (1 - sin x)/(π - 2x)²

Given, f is continuous at x \(=\frac{\pi}{2}\)