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in Continuity and Differentiability by (31.4k points)
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Find k if the function given below is continuous at  \(x=\frac{\pi}{2}\)

\(f(x) = \frac{2cos\,x - sin\,2x}{(\pi - 2x)^3},\) for \(x \neq \frac{\pi}{2}\)

f(x) = (2 cos x - sin 2x)/(π - 2x)3, for x ≠ π/2

= k, for \(x = \frac{\pi}{2}\)

1 Answer

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Best answer

f(x) = (2 cos x - sin 2x)/(π - 2x)3

Given, f is continuous at \(x = \frac{\pi}{2}\)

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