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in Physics by (22.7k points)

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω. How much current would flow through the 12 Ω resistor ?

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Best answer

Solution : 

Thus the current flow through 12 ohm resistance will be = V/R

I =9/13.4

I = 0.67 amp.

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