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in Physics by (22.7k points)

The circuit diagram given below shows the combination of three resistors R1 R2 and R3 :

Find : 

(i) total resistance of the circuit. 

(ii) total current flowing in the circuit. 

(iii) the potential difference across R1

1 Answer

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Solution : 

(i) Total resistance of two resistors that are connected in parallel is 

1/R’ = 1/3+1/6 

1/R’ = 3/6 

R’ = 2ohms 

Total resistance of the circuit = 2+4ohms = 6ohms 

(ii) Total current flowing through the circuit=V/total resistance

I = 12/6 = 2amps 

(iii) Potential difference across R1=R1 x I = 4 x 2 = 8V.

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