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A circle is drawn with the line joining (2, 3) and (6, 5) as diameter. What are the coordinates of the centre of the circle?

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ago by (31.1k points)

Midpoint of the line joining (2, 3) and (6, 5) is

\((\frac{x_1+x_3}{2},\frac{y_1+y_3}{2})=(\frac{2+6}{2},\frac{3+5}{2})\)

\((\frac{8}{2},\frac{8}{2})=(4,4)\)

∴ Centre of the circle is (4,4)

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