Question

The centre of a circle is (1, 2) and a point on it is (3, 2). Find the coordinates of the other end of the diameter through this point

Answer 1

Midpoint of the diameter

\((\frac{x+3}{2})=1,(\frac{y+2}{2})=2\)

x + 3 = 2

x = 2 - 3

x = -1

y + 2 = 4

y = 4 - 2

y = 2

The other end is (-1,2)