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in Arithmetic Progression by (15 points)
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A farmar borrows Rs. 1000 agrees to repay with a total interest of Rs. 140 in 12 monthly installment, each installment is being less than thee proceding installment is Rs. ____________.
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Repay with a total 12 instalments = Rs. 140
∴ Total of 12 installment S12 = Rs (1,000+140)
= Rs. 1140
Number of instalments (n)=12
Let first instalments =a
Difference (d)=−10

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