\(\frac{y-3}{x+1}=\frac{5-3}{2+1}=\frac{2}{3}\)
\(\frac{y-3}{x+1}=\frac{2}{3}\)
y - 3 = \(\frac{2}{3}(x+1)\)
y = \(\frac{2}{3}(x+1)+3\) \(\Rightarrow\) 2x - 3y + 11 = 0
If (x + 3, y + 2) is in this line, then
2(x + 3) - 3(y + 2) + 11 = 2x - 3y + 11 = 0
∴ (x + 3, y + 2) lies on this line