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Prove that whatever number we take as, the point (x, 2x + 3) is a point on the line joining (–1, 1) and (2, 7).

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Equation of line joined by (-1, 1) (2, 7)

\(\frac{y-1}{x+1}=\frac{7-1}{2+1}\)

\(\frac{y-1}{x+1}=\frac{6}{3}=2\)

y - 1 = 2(x + 1)

y = 2x + 2 + 1 = 2x + 3

y = 2x + 3

Slope of line joined by (-1,1), (x, 2x + 3)

\(\frac{2x+3-1}{x+1}=\frac{2x+2}{x+1}\) = 2

Slope of line joined by (2, 7), (x, 2x + 3)

\(=\frac{2x+3-7}{x-2}=\frac{2x-4}{x-2}=2\)

The slopes are same hence die point (x, 2x + 3) is passing through the points (–1, 1), (2, 7)

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