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HCF of (2^3 × 3^2 × 5), (2^2 × 3^3 × 5^2 ) and (2^4 × 3 × 5^3 × 7) is (a) 30 (b) 48 (c) 60 (d) 105

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HCF of (2 3 × 32 × 5), (2 2 × 33 × 52 ) and (2 4 × 3 × 53 × 7) is 

(a) 30 (b) 48 (c) 60 (d) 105

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(c) 60 

HCF = (23 × 32 × 5, 22 × 33 × 52 , 24 × 3 × 53 × 7) 

HCF = Product of smallest power of each common prime factor in the numbers 

= 22 × 3 × 5 

 = 60

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