B(2, -2), D(-2, 2) are the vertices of the diagonal BD: Sum of x, y coordinates of B = 2 + –2 = 0
Sum of x, y coordinates of D = –2 + 2 = 0
If (x, y)is a point on BD, then
\(\frac{y-2}{x+2}=\frac{2-2}{2+2}\)
\(\frac{y-2}{x+2}=\frac{4}{4}=1\)
y - 2 = -x - 2
y + x = 2 + 2 = 0
x + y = 0