Question

One end of the diameter of a circle is (1, 4). The center of the circle is (3, –4). Find the coordinates of other end

Answer 1

One end of the diameter = (x , y ) = (1, 4) 

Center of the circle = (x, y) =(3, -4) If other end of the diameter = (x₂, y₂)

\(3=\frac{1+x_2}{2},\)

∴ x₂ = 6 - 1

= 5 - 4 = \(\frac{4+y_2}{2},\)

∴ y₂ = -8 - 4 = -12,

Other end of the diameter (5 – 12)