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Find the slope of the line passing through (– 2, 3) (5, 7) Write the slope of the fine parallel to it.

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Slope of the line which passing through the points (–2, 3) and (5, 7) = \(\frac{7-3}{5+2}=\frac{4}{7}\)

The line which joins the points (–2, 2) and (5, 6) is parallel to the first line.

Slope of the line which passes through the points (–2, 2) and (5, 6) = \(\frac{6-2}{5+2}=\frac{4}{7}\)

Slope of the line which passes through the points (–7, 4) and (0, 8) = \(\frac{8-4}{0+7}=\frac{4}{7}\)

The lines are parallel because their slopes are same.

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