Question

In the parallelogram PQRS, P(-3, 2) Q(2, 7), S(1, 9) are three vertices. Find the length of the diagonal PR.

Answer 1

x coordinate of R = 2 + 1 – (–3) = 6

y coordinate of R = 9 + 7 – 2 = 14

(6, 14) is the coordinate of R

\(PR=\sqrt{((6-(-3))^2+((14-2))^2}\)

= \(\sqrt{9^2+12^2}\) = 15 unit