∴ Slope of the line joining (2, 3) and (3, –1)
\(=\frac{3-1}{2-3}=\frac{3+1}{-1}=-4\)
Slope of the line is –4
For point (5, –6)
Slope = \(\frac{6-3}{5-2}=\frac{3}{3}=1\)
Since slope = 4,
this line does not pass through (5,6)
For point (5, –9) Slope = \(\frac{-9-3}{5-2}=\frac{-12}{3}=4\)
The line (5, –9) pass through the point.