a. Let (5, 3) = (x1, y1) and (4, 1) = (x2, y2), = slop
= \(\frac{y_2-y_1}{x_2-x_1}=\frac{1-3}{4-5}=\frac{-2}{-1}=\frac{2}{1}=2\)
b. If the line meets x axis at the point (x, 0), then slope = \(\frac{a-3}{x-5}=2\)
\(\Rightarrow\) \(2(x-5)=-3\)
2x – 10 = –3,
2x = –3 + 10 = 7,
x = 7/2 = 3.5,
point is = (3.5, 0)
y axis \(\frac{y-3}{0-5}=2\) point (0, -7)
c. slope is (2/1) means when x coordinate increase/decreases by 1, y co-ordinate increases decreases by 2. Another point on
the line is (5 + 1), (3 + 2) = (6, 5)
A third point = (6 + 1) (5 + 2) = (7, 7)