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in NEET by (55 points)
A typical mobile phone of 5 V and an internal resistance of 200m ohms. What is the terminal potential of the battery when it supports a current of 500 m Ampere?

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1 Answer

+1 vote
by (24.8k points)

V = E-iR

= 5-(200 x 10-3 x 500 x 10-3)

= 5 - 0.1

= 4.9 V

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