Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
96 views
in Reactivity Series and Electrochemistry by (37.7k points)
closed by

Zn (s) + 2AgNO3 (aq) → Zn(NO3)2 (aq) + 2Ag 

a. Write the oxidation state of each element in this displacement reaction. 

b. Write the chemical equation for oxidation and reduction.

1 Answer

+1 vote
by (35.5k points)
selected by
 
Best answer

a. Zn° (s) + 2Ag1+N5+O2-3 (aq) → Zn2+ (N5+O2-3)2 (aq) + 2Ag°

b.Oxidation: 

Zn° (s) → Zn2+ (aq) + 2e- 

(Oxidation means losing of electrons)

Reduction: 

Ag1+ (aq) + le- → Ag (s) 

(Reduction means gaining of electrons)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...