Question

The direction of electron flow in certain galvanic cells are given below. (Symbols are not real) 

i. B → A, 

ii. E → C, 

iii. D → E, 

iv. A → D. 

a. Arrange the metals A, B, C, D and E in the decreasing order of their reactivity. 

b. Choose the reaction taking place at ‘C’ in cell (ii) E → C. Give the reason. 

i. C⁺ (aq) + le^- → C(s) 

ii. C (s) → C⁺ (aq) + le^-

iii. C (s) → C⁺ (aq) + le^-

Answer 1

a. B, 

A, 

D, 

E, 

C. 

b. C⁺ (aq) + le^- → C (s) is the correct equation. 

Because ‘E’ has higher reactivity than. So ‘C’undergoes reduction.