Fewpal
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1 Answer

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x2 - (m+1)x + m + 4 = 0

If the equation has ral roots, then the discriminant must be positive:

Let us verify:

d = b2 - 4ac > 0

==> (m+1)2 - 4*1* (m+4) > 0

==> m2 + 2m + 1 - 4m - 16 > 0

==> m2 -2m - 15  > 0

==> (m-5)(m+3) >0

==> m-5 > 0   and (m+3)>0   OR (m-5)< 0  and m+3 < 0

==> m > 5  and m > -3 OR m<5 and m<-3

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