We have 33/(2^2x 5) = 33x5/(2^2x 5^2) = 165/100 = 1.65

Now if a number is of type, n/(2^a x 5^b) where n is not a multiple of 2 or 5, then the number of digits after zero in this number will be either a and b, whichever is greater.

Hope it helps! Thanks