Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+2 votes
209k views
in Mathematics by (33.1k points)

Find the zeroes of the polynomial x2 – 3x – m(m + 3)

1 Answer

+2 votes
by (60.2k points)
selected by
 
Best answer

f(x) = x2 – 3x – m (m + 3) 

By adding and subtracting mx, we get 

f(x) = x2 – mx – 3x + mx – m (m + 3) 

= x[x – (m + 3)] + m[x – (m + 3)] 

= [x – (m + 3)] (x + m) 

f(x) = 0 ⇒ [x – (m + 3)] (x + m) = 0 

⇒ [x – (m + 3)] = 0 or (x + m) = 0 

⇒ x = m + 3 or x = –m 

So, the zeroes of f(x) are –m and +3.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...