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If (x + a) is a factor of (2x^2 + 2ax + 5x + 10), then find the value of a.

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If (x + a) is a factor of (2x2 + 2ax + 5x + 10), then find the value of a.

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Given: (x + a) is a factor of 2x2 + 2ax + 5x + 10 

We have 

x + a = 0 

⇒ x = –a 

Since, (x + a) is a factor of 2x2 + 2ax + 5x + 10 

Hence, It will satisfy the above polynomial 

∴ 2(–a)2 + 2a(–a) + 5(–a) + 10 = 0 

⇒ –5a + 10 = 0 

⇒ a = 2

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