Question

The area of one end of a U-tube is 0.01 m² and that of the other end the force 1 m², When a force was applied on the liquid at the first end?

Answer 1

A₁ = 0.01 m²

A₂ = 1 m²

F₁ = ?

F₂ = 20000 N

\(\frac{F_1}{F_2}=\frac{A_1}{A_2}\)

\(F_1=F_2\times\frac{A_1}{A_2}=20000\times\frac{0.01}{1}=200\,N\)