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A ball thrown vertically upward reached a maximum height of 20m 

(i) What was the velocity of the stone at the instant of throwing up? 

(ii) How much time did the ball take to reach the height 20 m?

2 Answers

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(i) v2 = u2 + 2as

u2 = v2 - 2as

= 02 - 2 x 10 x 20

= 400

u = 20 m/s

(ii) v = u + t

t = \(\frac{V-U}{a}\)

\(\frac{0-20}{-10}\)

= 2 s

0 votes
by (60 points)

\(v^2=u^2+2as\)
\(u^2=v^2-2as\)
\(=0^2-2(-10)(20) \)
=400
(i)u=20 m/s

\(v=u+at \)
0=20-10t 
20=10t 
(ii) t=2 sec

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