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Solve the equation : `2sin^(2)theta+sin^(2)theta=2` for `theta in (-pi,pi)`.

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Solve the equation : `2sin^(2)theta+sin^(2)theta=2` for `theta in (-pi,pi)`.
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`theta= {-pi/4, -(3pi)/4, -pi/2, pi/4, (3pi)/4, pi/2}`
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