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In a circle of diameter 40 cm. the length of a chord is 20 cm. Find the length of minor arc of the chord.

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Radius of circle, `=40/2` cm =20 cm
Now, OA=OB=20 cm and AB=20 cm
`rArr triangleOAB` is an equilateral triangle.
`therefore angleAOB=60^(@) = 60^(@) xx pi/180^(@)=pi/3` radian.
`therefore l = r.theta=20 xx pi/3 = 20/3 xx 22/7=440/21`
`rArr` Length of minor arc `=20.95` cm Ans.

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