Question

Find the general values of `theta` from the following equations:
i) `2cos^(2)theta+sintheta=0`
ii) `sin^(2)theta-2costheta+1/4=0`
iii) `tantheta-sintheta=sinthetatantheta-1`
iv) `sin^(2)theta-(1+sqrt(3))sinthetacostheta+sqrt(3)cos^(2)theta=0`

Answer 1

i) `theta=npi-(-1)^(n)pi/6`, ii) `theta=2npi+-pi/3`
ii) `theta=2npi+-pi/3`
iii) `theta=npi-pi/4, theta=npi+(-1)^(n).pi/2`
iv) `theta=npi+pi/4, theta=npi+pi/3`