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in Chemistry by (62.2k points)
de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :
A. `lambda = (12.3)/(sqrth) "Å"`
B. `lambda = (12.3)/(sqrtV) "Å"`
C. `lambda = (12.3)/(sqrtE) "Å"`
D. `lambda = (12.3)/(sqrtm) "Å"`

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1 Answer

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by (58.9k points)
Correct Answer - B

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