Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
46.9k views
in Physics by (54.6k points)

A simple harmonic oscillator is represented by the equation : Y = 0.40 Sin (440t+0.61) 

Y is in metres 

t is in seconds 

Find the values of 1) Amplitude 2) Angular frequency 3) Frequency of oscillation 4) Time period of oscillation, 5) Initial phase.

1 Answer

+1 vote
by (89.9k points)
selected by
 
Best answer

The given equation is:- Y = 0.40 Sin (440t + 0.61) 

Comparing it with equation of S.H.M. Y = a Sin (w t +∅0

1) Amplitude = a = 0.40m 

2) Angular frequency = w = 440Hz

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...