f(x) = x2- 4x+5
Since, given function is a polynomial which is defined everywhere.
Therefore, domain of function f(x) is set of all real numbers \((\mathbb{R}).\)
Now, f(x) = x2- 4x+5
= x2- 4x+4+1
= (x-2)2+1
≥ 0+1 (∵ (x-2)2 ≥ 0)
= 1
Hence, f(x) ≥ 1
⇒ f(x) ∈ [1, ∞)
Therefore, the range of function f(x) is [1, ∞).
Hence, domain of f(x) is \(\mathbb{R}.\)
And Range of f(x) is [1, ∞).