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A potential difference of 6V is applied across a conductor having 12Ω resistance.

How much current will pass through it? How many times will the current increase if length of the resistor is halved and potential difference is doubled?

1 Answer

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\(\text{I}=\frac{V}{R}=\frac{6}{12}=0.5\)A

If length is halved R = 12 × 1/2 = 6

potential difference V = 2 × 6 = 10V

\(\text{I}=\frac{V}{R}=\frac{12}{6}=2\)A

That is I is increased by 4 times.

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