Question

P, Q, R, S are four elements. Their atomic numbers are 8, 17, 12 and 16 respectively. Find the type of chemical bond in these compounds formed by combining the following pairs of elements. Construct and exhibit the type of bonds using different. substances (eg. pearls) (Electronegativity values: 

P = 3.44, Q = 3.16, R = 1.31, S = 2.5) 

(1) P, R 

(2) P, S 

(3) Q, R

Answer 1

1. PR 

Electronegativity difference = 3.44 – 1.31 = 2.13 The electronegativity difference is greater 1.7 it shows ionic compound. 

2. PS 

Electronegativity difference = 3.44 – 2.58 = 0.86 The electronegativity difference is less than 1.7 it shows covalent compound. 

3. QR 

The electronegativity difference = 3.16 – 1.31 = 1.85

The electronegativity difference is greater than 1.7 it shows ionic compound.