Question

The number of atoms in 100g of a fcc crystal with density=`10gcm^(-3)` and cell edge as 200gm, is equal to
A. `3xx10^(25)`
B. `5xx10^(24)`
C. `1xx10^(25)`
D. `2xx10^(25)`

Answer 1

(b) We know that, d `(Z.M)/(nxxa^(3))`
`n=(4xx100)/(10xx(200xx10^(-10))^(3))`
=`5xx10^(24)`