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Observe the following Python code carefully and obtain the output, which will appear on the screen after execution of it.

def Findoutput ():

L = "earn"

X = " "

count = 1

for i in L:

if i in ['a', 'e',' i', 'o', 'u']:

x = x + 1. Swapcase ()


if (count % 2 ! = 0):

x = x + str(len (L[:count]))


x = x + 1

count = count + 1

print x

Findoutput ()

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Best answer

The output is:


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