LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
23 views
in Chemistry by (67.0k points)
closed by
Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.

1 Answer

0 votes
by (63.1k points)
selected by
 
Best answer
(a) Reaction between Fe and `CI_(2)`
`Fe(Excess)+CI_(2)rarroverset(+2)FeCI_(2)`
`"(R.A) (O.A)(Lower O.S of Fe)"`
`Fe+CI_(2)(Excess)+O_(2)rarroverset(+3)FeCI_(3)`
"(R.A) (O.A) (Higher O.S of Fe)"
`(b) 2Fe(Excess)+O_(2)rarroverset(+2)2FeO`
`"(R.A) (O.A)(Lower O.S of Fe)"`
`2 Fe + 3O_(2)(Excess)rarroverset(+3)Fe_(2)O_(3)`
`"(R.A) (O.A)(Higher O.S of Fe)"`
(c) Xe `(Excess)+F_(2)rarroverset(+2)xeF_(2)`
`"(R.A)(O.A)(Lower O.S of Fe)"`
Xe + `2F_(2)(Excess)rarroverset(+4)XeF_(4)`
`"(R.A)(O.A)(Higher O.S of Xe)" `

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...