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Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will be
A. 2.5 mol
B. 0.2 mol
C. 0.6 mol
D. 0.4 mol

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The oxidising reaction is:
`2MnO_(4)^(-)+16H^(+)+5C_(2)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)`
`(2 mol)(5 mol)`
No of moles of `MnO_(4) "required oxidise 1 mole of ferrous oxalate" =5//2 mol=2.5 mol`

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