Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
216 views
in Chemistry by (67.2k points)
closed by
How many litres of `Cl_(2)` at STP will be liberated by the oxidation of `NaCl` with `10 g KMnO_(4)` in acidic medium: (Atomic weight: `Mn=55 and K=39)`
A. `3.54 litres`
B. `7.08 litres`
C. `1.77 litres`
D. none of these

1 Answer

0 votes
by (63.2k points)
selected by
 
Best answer
Correct Answer - A
Equivalents of `KMnO_(4)=` Equivalents of `Cl_(2)`
`{:(" 10"),(ulbar("158.04")),(" 5"):}`=n x 2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...