Solving the given equations, we have y2 = x and x2 = y ⇒ x4 = x or x4 – x = 0
⇒ x (x3 – 1) = 0 ⇒ x = 0, x = 1
Therefore, y = 0, y = 1
i.e. points of intersection are (0, 0) and (1, 1)
At (0, 0), the slope of the tangent to the curve y2 = x is parallel to y-axis and the tangent to the curve x2 = y is parallel to x-axis.
⇒ angle of intersection = π/2
At (1, 1), slope of the tangent to the curve y2 = x is equal to 1/2 and that of x2 = y is 2.