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Write the expression for the equilibrium constant `K_(c )` for each of the following reactions:
a. `2NOCl(g) hArr 2NO(g)+Cl_(2)(g)`
b. `2Cu(NO_(3))_(2)(s) hArr 2CuO(s)+4NO_(2)(g)+O_(2)(g)`
c. `CH_(3)COOC_(2)H_(5)(aq)+H_(2)O(1) hArr CH_(3)COOH(aq)+C_(2)H_(5)OH(aq)`
d. `Fe^(3+)(aq)+3OH^(Θ)(aq) hArr Fe(OH)_(3)(s)`
e. `I_(2)(s)+5F_(2) hArr 2IF_(5)`

1 Answer

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` (i) " "K_(c)=[[NO(g)]^(2)[CI_(2)(g)]]/([NOCI(g)]^(2)]`
` (ii) K_(c) = [[CuO(g)]^(2)[NO_(2)(g)]^(4)[O_(2)(g)]]/[[Cu(NO_(3))_(2)(s)]^(2)]=[NO_(2)(g)]^(4)[O_(2)(g)]`
`(iii) K_(c) =[[CH_(3)COOH(aq)][C_(2)H_(5)OH(aq)]]/[[CH_(3)COOC_(2)H_(5)(aq)][H_(2)O(l)]]=[[CH_(3)COOH(aq)][C_(2)H_(5)OH(aq)]]/[[CH_(3)COOC_(2)H_(5)(aq)]]`
`(iv) K_(c)=[[Fe(OH)_(3)(s)]]/([Fe^(3+)(aq)][OH^(-)(aq)]^(3)]=(1)/[[Fe^(3+)(aq)][OH^(-)(aq)]^(3)]`
`(v) K_(c)=[[IF_(5)(l)]^(2)]/[[I_(2)(s)][F_(2)(g)]^(5)]=[[IF_(5)(l)]^(2)]/[[F_(2)(g)]^(5)].`

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