Question

Equal volumes of 0.002 M solution of sodium iodate and cupric chlorate are mixed togather. Will it lead to precipitation of copper iodate?
`("for cupric iodate" K =7.4xx10^(-8))`.

Answer 1

Correct Answer - No precipitate
When equal volumes of sodium iodate and cupric chlorate solutions are mixed together, then the molar concentrations of both solutions are reduced to half i.e., 0.001 M.
`{:(Na10_(3),rarr,Na^(+),,+,10_(3)^(-),),(0.001M,,,,,0.001M,):}`
`{:(Cu(ClO_(3))_(2),rarrCu^(2+),+,2ClO_(3)^(-)),(0.001M,,,0.001M):}`
Now, the solubility equilibrium for copper iodate can be written as:
`Cu(10_(3))_(2) rarr Cu_((aq))^(2+) + 210_(3(aq))^(-)`
Ionic product of copper iodate:
`[Cu^(2+)][10_(3)^(-)]^(2)`
`= (0.001)(0.001)^(2)`
`= 1 xx 10^(-9)`
Since the ionic product `(1 xx 10^(-9))` is less than `K_(sp) (7.4 xx 10^(-8))`, precipitation will not occur.