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The `K_(sp)` of `Ag_(2)CrO_(4)`, AgCl, A gBr and AgI are respectively `1.1xx10^(-12), 1.8xx10^(-6), 5.0xx10^(-13) and 8.3xx10^(-17)`. Which one of the following salts will precipitate last if `AgNO_(3)`solution is added to the solution containing equal moles of NaCl, NaBr, NaI and `Na_(2)CrO_(4)`?
A. AgBr
B. `Ag_(2)CrO_(4)`
C. AgI
D. AgCl

1 Answer

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Correct Answer - B
`Ag_(2)CrO_(4)hArr2Ag+CrO_(4)^(2-), K_(sp)=(2s)^(2)xxs=4s^(3), s=((K_(sp))/(4))^(1//3)=((1.1xx10^(-12))/(4))^(1//3)`
`=0.65xx10^(-4)`
`AgCl hArr Ag^(+)+Cl^(-),K_(sp)=sxxs=s^(2)`,
`s=sqrt(K_(sp))=sqrt(1.8xx10^(-10))=1.34xx10^(-5)`
`AgBr hArr Ag^(+)+Br^(-), K_(sp)=sxxs=s^(2)`,
`s=sqrt(K_(sp))=sqrt(5.0xx10^(-13))=0.71xx10^(-6)`
`AgI hArr Ag^(+)+I, K_(sp)=sxxs=s^(2)`,
`s=sqrt(K_(sp))=sqrt(8.3xx10^(-17))=0.9xx10^(-8)`
As solubility of `Ag_(2)CrO_(4)` is highest, it will be precipitated last of all.

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