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`K_(a) ` for `CH_(3)CO OH` is `1.8xx10^(-5) and K_(b)` for `NH_(4)OH ` is `1.8xx10^(-5)`. The pH of ammonium acetate will be

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`K_(a) ` for `CH_(3)CO OH` is `1.8xx10^(-5) and K_(b)` for `NH_(4)OH ` is `1.8xx10^(-5)`. The pH of ammonium acetate will be
A. 7.005
B. 4.75
C. `7.0`
D. between 6 and 7.
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Correct Answer - C
`CH_(3)CO ONH_(4)` is a salt of weak acid and weak base. Hence,
`pH = 7 + (1)/(2) (pK_(a) - pK_(b))=7+0=7`
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