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The solubility product constants of `Ag_(2)CrO_(4)` and AgBr are `1.1xx10^(-12) and 5.0xx10^(-13)` respectively. Calculate the ratio of molarities of

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The solubility product constants of `Ag_(2)CrO_(4)` and AgBr are `1.1xx10^(-12) and 5.0xx10^(-13)` respectively. Calculate the ratio of molarities of their saturated solutions.

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Correct Answer - `(S(Ag_(2)CrO_(4)) )/(S(AgBr))=(6.5xx10^(-5)M)/(7.07xx10^(-7))=91.9`
Calculate their solubilities separately and then calculate the ratio.
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