Question

The value of `K_(c) = 4* 24` at 800 K for the reaction,
` CO (g) + H_(2)O (g) hArr CO_(2) (g) + H_(2) (g)`
Calculate equilibrium concentrations of `CO_(2) , H_(2) , CO and H_(2) O " at 800 K, if only CO and " H_(2)O ` are present initially at concentration of ` 0*10` M each ?

Answer 1

` {:(,CO(g),+,H_(2)O(g),hArr,CO_(2)(g),+,H_(2)(g)),("Intial conc.",0*1 M,,0*1M,,,,),(" AT . eqm.",0*1-x,,0*1-x,,x,,x):}`
`K_(c) = ([CO_(2)][H_(2)])/([CO][H_(2)O]) :. 4* 24 = x^(2)/(0*1-x)^(2)`
or `x/(0*1 - x)= 2*06 or x = 2*06 (0*1-x) or x= 0*206 - 2*06 x or 3*06 x = 0*206 or x = 0*067`
`:. [CO_(2)]_(eq) = [H_(2)O]_(eq) = 0*067 M, [CO]_(eq) = [H_(2O] _(eq) = 0*1 - 0*067 = 0*033 M`