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Calculate the `H_(3)O^(+)` ion concentration of a solution having pH 6.58.

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`pH = - log [H_(3)O^(+)] :. Log [H_(3)O^(+)]=-pH = - 6.58 ` {pH = 6.58, given }
`:. [H_(3)O^(+)]` = antilog (-6.58) = antilog `bar(7) .42=2.63xx10^(-7) ` g ions/litre

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