Question

What will be the pressure exerted by a mixture of 3.2 g of methane and 4.4 g of carbon dioxide contained in a 9 `dm^(3)` flask at `27^(@)C` ?

Answer 1

`p=(n)/(V)"RT"=(w)/(M)(RT)/(V)`
`P_(CH_(4))=((3.2)/(16)"mol")(0.0821 dm^(3) atm K^(-1)xx300 K)/(9 dm^(3))=0.55 atm`
`P_(CO_(2))=((44)/(44)"mol")(0.0821 dm^(3)" atm "K^(-1)mol^(-1)xx300 K)/(9 dm^(3))=0.27 atm`
`P_("Total")=0.55+0.27=0.82 atm`
In terms of SI units, `" "R=8.314 Pa m^(3) K^(-1)mol^(-1), V=9xx10^(-3)m^(3)`
`P=5.543xx10^(4) Pa+2.771xx10^(4) Pa=8.314xx10^(4) Pa`.