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Calculate the temperature of 4.0 moles of a gas occupying 5 `dm^(3)` at 3.32 bar (R=0.083 bar `dm^(3)K^(-1)mol^(-1)`)

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PV=nRT or `T=(PV)/(nR)=(3.32" abr"xx5dm^(3))/(4.0 molxx0.083" bar" dm^(3)K^(-1)mol^(-1))=50 K`

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