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Find p(0), p(1) and p(-1) in the following polynomials,

i. p(x) = 3x + 5

ii. p(x) = 3x2 + 6x + 1

iii. p(x) = 2x2 – 3x + 4

iv. p(x) = 4x3 + 2×2 + 3x + 7

v. p(x) = 5x3 – x2 + 2x – 3

1 Answer

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Best answer

i. p(x) = 3x + 5 

p(0) = 3 × 0 + 5 = 5 

p(1) = 3 × 1 + 5 = 8 

p(-1) = 3 x - 1 + 5 = 2

ii. p(x) = 3x2 + 6x + 1 

p(0) = 3 × 02 + 6 × 0 + 1 = 1

p(1) = 3 × 12 + 6 × 1 + 1 = 10 

p(-1) = 3 × (-1)2 + 6 × (-1) + 1 = -2

iii. p(x) = 2x2 – 3x + 4 

p(0) = 2 × 02 – 3 × 0 + 4 = 4 

p(1) = 2 × 12 – 3 × 1 + 4 = 3 

p(-1) =2 × (-1)2 – 3 × (-1) + 4 = 9

iv. p(x) = 4x3 + 2x2 + 3x + 7 

p(0) = 4 × 03 + 2 × 02 + 3 × 0 +7 = 7 

p(1) = 4 × 13 + 2 × 12 + 3 × 1 + 7 = 16 

p(-1) = 4 × (-1)3 + 2 × (-1)2 + 3 × (-1) +7 = 2

v. p(x) = 5x3 – x2 + 2x – 3 

p(0) = 5 × 03 – 02 + 2 × 0 – 3 =-3 

p(1) = 5 × 13 – 12 + 2 × 1 – 3 = 3 

p(-1) = 5 × (-1)3 – (-1)2 + 2 × (-1) – 3 = -11

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